Oh my lecturer has found the value for x in an earlier question.
X = F/k = (1200*9.81)/3.5*10^6 = 3.36 mm
and he said this value is the static deflection of the loaded system from equilibrium. Which means he is considering the cable and magnet to be one system. So yeah he is considering X to...
Immediately after its released the tension would be the same as before for a split second. this is probably why the magnet would be suddenly pulled upwards. Then the cable will become slack...is that correct?
Thanks TSny...
So basically what you are saying is that Fmax is equal to the difference between the tension right before the car is dropped and the weight of the magnet??
Since that tension is greater than the weight of the magnet, the resultant(Fmax) would point upwards like we agreed
I was trying to solve this question:
In a scrap yard, a car of mass 1200 kg is suspended from a crane using an electromagnet of mass 1400 kg.When the electricity is turned off the car is dropped. Assuming the spring constant for the crane and the supporting cable is 3.5 MN/m, find the maximum...
I was working on a question where I had to find the maximum shear stress in a I-beam due to a shear force applied on it. Heres the question :
An I girder 600 mm x 300 mm has flanges 25 mm thick and a web 13 mm thick. Find the maximum shear stress due to a shear force of 500 kN and compare this...
In that case isn't it supposed to be P=(2*Pi^2*EI)/L^2, instead of P=(4*Pi^2*EI)/L^2
Because if the beam is like 2 struts joined end to end, there will be 2 deflections. The top half and the bottom half would deflect right? How does the equation have a 4 in it?
I was trying to solve a question where they told me to find the buckling load of a wing strut in a plane that experiences a compressive load along its axis. The strut can be considered to be a pin-jointed at both ends. Dimensions of the strut is as follows: outside diameter is 150 mm and...