Greetings, I faced with a problem that states - Find slope of the tangent line to 〖 x〗^4 –
xy^2+ 4xy^2 = 20,at (1,2)
First I set F= x^4 – xy^2+ 4xy^2-20=0
I found dF/dx = 4x^3 + y^2+ 4y^2= 24 ,at (1,2)
then dF/dy = 2xy+8xy,=20 at (1,2) …. Armed with this I then made the...