Hey Everybody.
I was just wondering about this query:
lim((cosx/x^2)-(sinx)/x^3))
x->0
My teacher is telling me to use L'hopital, but the problem is that
the first part (cosx)/(x^2) isn't a "0/0", cosx-> 1 for x->0
So what should I do, i know the right answer is -1/3, but i need...