Recent content by nikoladjal

Hello, Vanadium 50, thank you for your response. That's the problem here, I don't have the figure of an advisor yet, we have to talk with the professor we think that fits best to the topic we have in mind, but I still don't have anyone. I'm asking to get some good ideas and clearing my mind...

Hello all, I'm doing a Master's Degree in Theoretical Astrophysics and now I need to decide in which topic I will do my final project and I wanted to ask you what would be the best option. I would like to do something that would make me have some future in the investigational path I choose...

I think I' ve finally made it. In the space we are working in, we can take symmetry and identify <x>=<p>=0 because all the states have the same probability. With this, I minimised the inequality we discussed before in the value c=b/a and I introduced the result of this back in the inequality...

Yes, a and b are complex, but I think that doesn't interferes with the calculus I made, no? I can't see neither the correlation between σxσp and my result, but the tip they give to us is that it can be made with the condition <Ψa|Ψa>=>0. and that's the only expression I could reach for that...

My fault, the a and b are there, I forgot to include them. I'll put here the guideline I followed (I'm not sure it's right): I began with this (where x and p are the operators position and momentum): <Ψa|Ψa>= ∫Ψ*(ax-ibp)·Ψ(ax+ibp)dV = ∫Ψ*(##a^2##·##x^2##+##b^2##·##p^2##+iab(xp-px))Ψ adV =...

Thank you BvU. Here is some information about the procedure I followed. I used the condition for <Ψa|Ψa> having to be equal or greater than zero, and I solved the integral. I did the substitution of the operators x and p, and I have the following expression: <Ψa|Ψa>=...

1. Homework Statement I have to demonstrate the Uncertainty Principle Starting from the expression of the following ket: |Ψa>=(ax^+ibp^)|Ψ> where a and b are complex numbers and the ^ denotes that x and p are unitary vectors. 2.Relevant equations I must use the bra-ket notation, but I...