Recent content by Nil.Recurring

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    Voltage Divider Bias Under Load

    It gives us stability! :D
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    Voltage Divider Bias Under Load

    One more question, regarding voltage drop across Rc... you mentioned that I need to drop Vcc/2 on Rc to get the most symmetrical voltage gain, right? But wouldn't that be the case if there is no emitter resistance? If there is an em-miter resistance I would need to center the output wave...
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    Voltage Divider Bias Under Load

    Ie is slighty greater then Ic. Ie = Ic + Ib. Vb = 0.7 + Ve. So there's a 0.7 V difference. Temperature would affect beta. A capacitor would increase the gain of the AC signal as it would allow it to bypass Re (which reduces gain). Don't know about your other questions. I haven't really...
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    Voltage Divider Bias Under Load

    Thanks for the link.. 2 - Av = - RC/RE (if I'm not mistaken) 3 - I would bias it slightly below Vcc/2 as that would clip the signal because the 'allowable voltage' (voltage that can pass through without clipping) would be lower then set by Av... and so the signal would be clipped. I hope that...
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    Voltage Divider Bias Under Load

    No, I meant the load is in parallel with the collector. One terminal of the load (RL) is connected between Rc and and the collector terminal. The other terminal of RL is grounded. So effectively, it has Vc across it. What I want to know how do I calculate the various voltages and currents in...
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    Voltage Divider Bias Under Load

    Hey, I'm kinda stuck in this odd question. I've tried searching on the Internet but haven't found much help. Basically, I have a voltage divider biased transistor. I can solve and find its Q-point without an external load, but I'm kinda confused how the circuit will change when there is an...
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