Thanks for the advice, it was spot on! The correct formula for the Laplacian in polar coordinates is
Δ2ψ = r-1δ/δr(r*δψ/δr) + r-2(δ2ψ/δθ2)
Plugging in, we have:
r-1δ/δr[-r*cαr(α-1)sin(αθ)] + r-2[cα2rαsin(αθ)]
Differentiating the first term and simplifying, we have
-cαr(α-2)sin(αθ) -...
Homework Statement
"The flow of a fluid past a wedge is described by the potential
ψ(r,θ) = -crαsin(αθ),
where c and α are constants, and (r,θ) are the cylindrical coordinates of a point in the fluid (the potential is independent of z). Verify that this function satisfies Laplace's...