Recent content by nito18

thanks :)

yes, sorry. is: $$ \mathcal L^{-1}\frac 1 {(s^2+1)^2}$$ so $$ \mathcal L^{-1}\frac 1 {(s^2+1)} * \frac 1 {(s^2+1) }$$ then f(τ) = sen τ g(t-τ) = sen (t-τ) ∫ sen τ * sen (t-τ) dτ Integration by parts u= sen (t-τ) du = -cos(t-τ) dv= sen τ dτ v= -cos τ ∫ sen τ *...

Homework Statement Hi. I need help to resolve the inverse laplace transform of {1/((x^2)+1)^2}2. The attempt at a solution I have tried to do: {(1/((x^2)+1) * (1/((x^2)+1)} then, convolution, sen x But, isn't working Thanks for your help :)