Recent content by nivaOne

Hi, I'm woundering whether this circuit has some kind of dedicated name in the field? https://dl.dropboxusercontent.com/u/22589354/VoltageDivider2.jpg It's not just the average voltage divider as it it influences the serial part as well the parallel part in the same time. And does...

Hi Fish, Can you please have a look at your calculations again? I'm wondering where the 5V came from, I assume that you should have used 15V instead (26-15 = 11V) regards NivaOne

Thank you, Fish, v6kro, Adjuster. I have learned a lot from your remarks. A few extra remarks: This project is indeed not a trivial project. The cycle is actually a moped which we consider a very lightweight motor cycle (sorry for the confusion, English is not my mother language ) We...

Thank you Bob. It definitely is a dynamo. The higher the RPM, the higher the voltage output. There is no feedback path, hence no possibility to control it otherwise then via extra hardware behind the output.

Hi Fish Many thanks for your advice. The motorcycle dates from 1984 as well as the spare engine that came from a different brand. Both are not on the market anymore. I have visited multiple service points, without success however. The load regulator present today just can't deal with that...

Hi, I'm trying to make a voltage limiter for my kid's motorcycle. The engine has been replaced. It came with a different alternator. And the voltages are way too high now. The rectified output varies between 15 and 26v DC. I'm trying to design a circuit which provides an output of max...

Hi Does 'Karnaugh' ring a bell to you? http://en.wikipedia.org/wiki/Karnaugh_map If so, it's an alternative way that can lead to the answer.

it does state Kirchhoff : "The total current flowing into a point is equal to the current flowing out of that point" AND "The potential differences around a circuit add up to zero" They look like laws to me.

you can start here http://www.antonine-education.co.uk/physics_as/module_3/Topic_3/kirchhoff.htm Regard Kirchhoff as principles rather then formulas. Try to understand them rather then purely applying them. Combine them with Ohm's law in linear circuits to calculate the results...

Hi, If you look at each signal individually, you would only see signals with the same shape and frequency. But if you would use an oscilloscope, you would see the difference.

Consider it a pulley. If you pull the rope downwards then the other side goes upwards. And vice versa. So it means when the input voltage rises, the output voltage will lower.

Hi Lowrie, Inductors do not like change. Which means they will try to block current upon applying power to the circuit. ( DC power that is ). A capacitor does the opposite, it acts as a short circuit in the beginning and ends as an extreme high value resistor. An inductor will act as extreme...

Hi Roan, The answer lies in the fact that in this case "I1 and I2 are determined by R1 and R2 respectively" If you can determine the voltages across these resistors then you can calculate the currents. There is no resistor in the arm containing DV3. So the voltage across the left and...

I have changed the drawing a little bit. Try to find out what the voltages are over every component in the left and middle arm ! Realise the following in this circuit: - between points A and B, there can only be a "single" potential difference. - the sum of the voltages in an arm equals...