Recent content by Notyou

Oh geeze, I just figured out what I did wrong. I wrote it down as .65 instead of .065. Thank you a lot for your help!

Hmm... I suppose with KE final I assumed it meant when the arrow hits the ground. So... I had it backwards? Did I just interpret the question wrong?

Homework Statement A 0.065 kg arrow is fired horizontally. The bowstring exerts an average force of 70 N on the arrow over a distance of 0.90 m. With what speed does the arrow leave the bow? Homework Equations W=Fd W=KE final - KE initial KE= 1/2mv^2 The Attempt at a Solution...

Figured it out <_<. The force was acting on the objects independently. What I don't really understand though, is how come in this scenario the same force is acting independently on the objects but if I laid the two blocks on a flat surface and pulled the heavier block with a string the force...

Homework Statement Two objects are hanging from a pulley. One has a mass of 12kg and another has a mass of 10kg. Initially, the two masses are at rest and friction is ignored. Once in motion, find the tension in the string and the acceleration of each of the two masses.Homework Equations...

I got it now. The weight of the helicopter does not matter in this question. The acceleration of the car is 9.8 plus .6 acting in the positive direction. So... force would be the mass of the car times 10.4. Thank you so much!

The rope is pulling on the car in the positive direction... and that force would be equal to the force of the weight due to Newton's third law correct?

Alright. The forces working against the car in the negative direction would be the weight of the car x acceleration due to gravity. The forces working on the car in the positive direction would be the force of the helicopter x gravity. That seems to only be the case if the whole scenario were...

Homework Statement A 6000kg helicopter accelerates upward at .6m/s^2 while lifting a 1500kg car. What is the tension in the cable (ignore the cable mass) that connects the car to the helicopter? Homework Equations F=MA The Attempt at a Solution Alright... so here's what I've been...