Recent content by nslinker
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Linear expansion coefficient of glass
the given dimensions + expansion value.- nslinker
- Post #7
- Forum: Introductory Physics Homework Help
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Linear expansion coefficient of glass
My answer from that comes out to be 2.36 but I don't know how to find the minimum spacing piece that you're talking about.- nslinker
- Post #5
- Forum: Introductory Physics Homework Help
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Linear expansion coefficient of glass
I did not change to degrees Celsius. The conversion is (5/9)*(150-32) so my new temp is 65.556. Also, I have to change cm -> mm. so the dimension would be 4000 mm. So, my final equation would be (9e-6)(4000)(65.556) ??- nslinker
- Post #3
- Forum: Introductory Physics Homework Help
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Linear expansion coefficient of glass
Given: The linear expansion coefficient of glass is 9 × 10−6 (◦C)−1. An automobile windshield has dimensions of 60 cm by 400 cm. What minimum spacing around the wind-shield is needed to prevent the windshield from breaking if the temperature changes by 150◦F? Answer in units of mm. I...- nslinker
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- Coefficient Expansion Glass Linear Linear expansion
- Replies: 8
- Forum: Introductory Physics Homework Help
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Calculate Internal Resistance: I, R, V & More
Well, the question says "A 20 V battery delivers 107 mA of current when connected to a 74 ohm resistor. Determine the internal resistance of the battery."- nslinker
- Post #3
- Forum: Introductory Physics Homework Help
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Calculate Internal Resistance: I, R, V & More
How can I go about calculating internal resistance? I have variables I, R, and V but no idea on how to find the 'internal' resistance. Is this some sort of special case?- nslinker
- Thread
- Internal Internal resistance Resistance
- Replies: 3
- Forum: Introductory Physics Homework Help
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Finding magnitude of surface charge density.
If given variables A, d, V, and constant 8.854e-12. How can I find the magnitude of surface charge density. I originally used Sigma = Q/A but I am not getting the right answer. Any help is appreciated! :)- nslinker
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- Charge Charge density Density Magnitude Surface Surface charge density
- Replies: 1
- Forum: Introductory Physics Homework Help
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Defining Flux in the Context of Electric Fields
so just 1.24 m x (6.33 x 10 ^5)?- nslinker
- Post #9
- Forum: Introductory Physics Homework Help
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Defining Flux in the Context of Electric Fields
So, there is no integration involved, just multiplication?- nslinker
- Post #7
- Forum: Introductory Physics Homework Help
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Defining Flux in the Context of Electric Fields
After reading it, I still don't know how to get to the correct equation, whether it's just plug-and-chug or if I have to integrate.- nslinker
- Post #5
- Forum: Introductory Physics Homework Help
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Defining Flux in the Context of Electric Fields
Even though an electric field doesn't actually "flow," I think of it as the flow of electric field vectors, either inward or outward.- nslinker
- Post #3
- Forum: Introductory Physics Homework Help
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Defining Flux in the Context of Electric Fields
A 124 cm diameter loop is rotated in a uniform electric field until the position of the maximum electric flux is found. The flux in this position is measured to be 6.33 x 105. What is the electric field strength?- nslinker
- Thread
- Electric Electric field Electric field strength Field Field strength Strength
- Replies: 9
- Forum: Introductory Physics Homework Help
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Calculating Electric Flux Through a Cube: A Simple Guide
Wow...you were all right; much simpler than I ever thought it was. Thanks to all of you for putting up with my stupidity for the time being. I am sure I will need more help soon and down the road [next week probably :) ] and I would be glad to get your guys help again. Thanks again!- nslinker
- Post #27
- Forum: Introductory Physics Homework Help
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Calculating Electric Flux Through a Cube: A Simple Guide
2.258e5 Nm2/C- nslinker
- Post #25
- Forum: Introductory Physics Homework Help
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Calculating Electric Flux Through a Cube: A Simple Guide
2.258 x 105 ?- nslinker
- Post #23
- Forum: Introductory Physics Homework Help