Recent content by odporko
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Very important, Lagrange multiplier
Thank you very much, you really really helped me probably pass the most important subject this semester :)- odporko
- Post #10
- Forum: Calculus and Beyond Homework Help
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Very important, Lagrange multiplier
4*(1/450868486864896*λ^(11/3))^(1/5)+ 6*(1/ 812479653374328*λ^(13/4))^(1/5)-720=0 well this is the equation after i get x and y and now i am pretty sure i did something wrong...- odporko
- Post #7
- Forum: Calculus and Beyond Homework Help
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Very important, Lagrange multiplier
it goes for y=(1/ 812 479 653 374 328*λ^(13/4))^(1/5)... and now my mind already blew up- odporko
- Post #6
- Forum: Calculus and Beyond Homework Help
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O
Very important, Lagrange multiplier
1. Homework Statement f(x,y) = x^(1/4)*y^(1/3), g(x,y) = 4*x +6*y=720 sorry i had a mistake before 2. Homework Equations ∇f=λ∇g y^(1/3)/(4*x^(3/4))= 4*λ x^(1/4)/(3*y^(2/3))= 6*λ these are partial derivations, and we want to express y just with lambda and here is something that really...- odporko
- Post #5
- Forum: Calculus and Beyond Homework Help
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Very important, Lagrange multiplier
L ( x , y ) = x^(1/4) + y^(1/3) + λ ( 4*x + 6*y − 720 ) I am not able to partialy derivate this equation, it always has weird numbers and after that i am not able to continue because i don't understand L. multiplier very well.- odporko
- Post #3
- Forum: Calculus and Beyond Homework Help
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Very important, Lagrange multiplier
Guys, i would be really greatfull if someone help me with this because i really don't know how to deal with this math problem: Find the maximum and minimum values of f = x^(1/4) + y^(1/3) on the boundary of g = 4*x+ 6*y = 720. Please help me someone, i am desperate from this :(- odporko
- Thread
- Important Lagrange Lagrange multiplier
- Replies: 10
- Forum: Calculus and Beyond Homework Help