Recent content by oferon

But on both processes I start with same Pi and Vi, and end up with same Pf and Vf. I thought E is a state function, so it should not matter how I reached from initial to final state. If it's an ideal gas, then for same P and V I must get same T, regardless of any bath... What am I missing?

I'm sure there are more than two ways, but I'm asking about these two. First is to relase the piston at once (getting a new constant external pressure). Second is to release it in very small steps (thus temprature remains constant). As far as I see we have the same Ef and Ei, because it should...

I have a cylinder with gas in it. I can make it expand in two ways: spontaneously isobaric process or reversible isothermal process. I understand W and Q for each process are different, but is ΔE the same? If not - why?

I would need to know iso, sec and tert for my exam.. Some answers you should pick appear as iso\sec\tert rather than IUPAC formal names.. I wish it wasn't like that

Why not? Here is sec-butylcyclohexane: And another carbon to the chain simply makes it pentyl, am I wrong?

any iso/sec/tert name for it?

http://img43.imageshack.us/img43/2916/95953925.jpg I understand molecule #1 is sec-pentylcyclohexane But how would you call molecule 2? Please give common and IUPAC names (no need for too much detailed explanations) Thank you.

Hi gustav Thanks for your reply Could you just explain what "s.t." means? I'm not very familiar with the english terms. Thanks a bunch

I never used discrete math terms in english before, so I hope it sounds clear enough: Formalize the following: 1) Between every two different real numbers there is a rational number 2) There exist real numbers x and y, such that x is smaller than y, yet x^2 is bigger than y^2 Now the solution...

OK, please discard all of my question, I'm an idiot :) Everything is clear now, I thank you very much for the last time :)

Oh ok, I discard my 3rd question... The answer is that I pick v2 to be \begin{pmatrix} 1 \\ -1 \\ 1 \\ -1 \end{pmatrix} Now I remain only with questions 1, and 2.. More related to equations system rather than J form I suppose

Hmm, ok I see what you say.. So now I have 3 final questions to close this case for good: 1) I thought all solutions were given by span of \begin{pmatrix} 1 \\ 0 \\ 1 \\ -2 \end{pmatrix} , \begin{pmatrix} 0 \\ 1 \\ 0 \\ -1 \end{pmatrix} So where did this \begin{pmatrix} 0 \\ 0 \\ 0 \\ 1...

Ok, so I asked our instructor about the second question and yes, both methods are good. I prefer "my" method, but as you can see I still get stucked with it.. So how do I move on with this (A-3I)v_3 = λv_2+μv_4 ? Thanks again

Hi, thanks for your kind replies. Ok, first I try what you suggested.. I take (A-3I)v_3 = λv_2+μv_4 I get: \begin{pmatrix} 1 & 1 & 1 & 1 \\ -1 & -1 & -1 & -1 \\ 6 & 1 & -4 & 1 \\ -6 & -1 & 4 & -1 \end{pmatrix}\begin{pmatrix} x \\ y \\ z \\ w \end{pmatrix}=\begin{pmatrix} λ \\ μ \\ λ \\...

If it was a linear combination of other vectors then V1-4 would not be a basis.. Am I wrong? Plus, another student told me the method I tried was completely wrong and that the correct method is finding more vectors through Ker (A-λI)^j where j=2,3,... depends on how many more vectors I need...