Recent content by oh.rry21

So I'm trying to understand a couple things regarding this. lets say we have a plate that's charged to Q. and we want to find the E field of a point .1 meters above the plate. when i looked at the solution, it never took the .1 meters into account when calculating the strength of the E...

it absolutely corresponds to what i have in mind. except the magnetic field is decreasing its exactly what i have in mind okay so F=qE i have as going in the negative y direction and as for the v x b, with its velocty vector in the negative y direction and the b field going into the page...i...

T_T I am so confused jandl and nick89. i don't know if i did anything right or wrong what does the proton actually do? haha :( i'm the kind of person who can learn from the answer rather than the means of getting there. it'll make a lot more sense to me if i knew what happened and i filled in...

touche. hahaha no its a circular magnetic field :)

sorry :X hahaha okay so its a uniform magnetic field pointing into the page, decreasing at some rate. its actually a circular magnetic field with some radius R and the proton is in the magnetic field. the question asks "when it is released from rest, what happens to the proton?" okay...

well yeah. that's why i added the E and v x b vectors. am i wrong?

right but when i did the cross product of f=q vxb... the velocity vector is to the left. and I'm assuming that my "b" is the induced magnetic field. the induced magnetic field points out in the same direction as the magnetic field (since its decreasing). and so i get the magnetic field as...

well if the current carrying wire is going "out of the page" (negative Z direction?) then the electron would be traveling along the (negative X axis) to be supposedly deflected downward into the negative Y direction is that the same direction as the direction of the magnetic field then?

so the proton will be pushed to the left because of the local electric field created by a collapsing magnetic field? but when the proton starts accelerating (assuming its to the left), doesn't the decreasing magnetic field and the velocity vector of the now moving proton exert a force? if...

so i know this is a classical experiment but I am having trouble understanding this idea. basically the experiment shoots an electron at a current charged wire (current coming "out of the page"). Does increasing/decreasing the current change the trajectory of the electron. and if so/if not...

sorry i didnt follow the template but its a conceptual question I'm not sure i understand. if there's a proton in a decreasing magnetic field... will it move or anything? according to my deductions, it won't have any forces on it and therefore it won't move. although there will be an...

wait how did you know that U_o is 1/sq(2) of Q_o? i know there's easy algebra involved x_x haha but i don't see how you got there

so at the end of the day. the induced emf (the E field) will exert a force on the proton, but as the proton moves, there will be a magnetic force on the proton (cross product of its velocity and the magnetic field)? in terms of vectors then...can i expect it to move wherever the resultant...

so the induced EMF (E) will exert a force on the proton F=qE then? So... i use faraday's law to determine the E and just multiply it by q?

but even if i had that equation...how would i use it in relation to the RC equations? just because i have an energy equation in terms of capacitance and voltage doesn't mean i can find the time it takes for it to decay to 50%of its original energy.