This is a question where the answer is given but I don't understand how to derive it.
The answer to the homogeneous eq. is: A cosh(x) + B sinh(x) with no explanation of how it is arrived at and the given answer then goes on to describe how the non-homogeneous part is solved.
Diff. eq. ...
This is not a homework question but one that is part of the course material and I can't really move on until I understand the basic calculus.
I have a problem interpreting "d by dx of partial dF by dy' equals partial d by dy' of dF by dx" in the following question, which I set out and then...