Ohh, I think I get it now. Because in a DC voltage divider, the dropped voltage across R1 minus that of R2 is the voltage (or maybe the voltage is just R1 to ground and I'm stupid, either way) then as the capacitor R2's "resistance" decreases, there will be less of a gradient between R1's drop...
Ok, I can see now from that article that a capacitor's reactance decreases as frequency increases, because there is less charge accumulated that a current would have to "move" in between polarity shifts. But why would that cancel out frequency ripples? (Sorry if I'm bothering you XD)
Hmm, that's sort of what I was thinking. If you use only one resistor, a voltmeter will just read the potential between the positive and negative. But if you have a resistor between the positive cable of your voltmeter and ground, it will make current flow?
Hmmm. So I don't know what the resistor is for, but it looks like the capacitor charges like a shock absorber, to level out voltage swings? And maybe the resistor is supposed to cancel out the capacitor's discharge when the AC wave flows backwards?
Hi! I'm working on a project in which a small microcontroller with a max. analog input of 5v takes readings from multiple sensors. I would like to make this input window a bit more versatile, and turned to voltage dividers as a solution. 'Problem is, I'm having a bit of trouble understanding how...
Ja, I've looked into LC oscillators, but they're a bit confusing when it comes to actually making them. I'm going off of some projects I saw on the web of people using 1-20 MHz clock crystals as modulators.
Hi everyone! This is my first thread :)
I've been working a bit with AC and radio, and would like to make a simple(-ish) circuit in which a 1-volt peak audio signal is stepped up to around 5 volts with a transformer, and is fed into a crystal oscillator to make a crude-but-effective AM...