So if I let x be the distance from the edge of the table to the center of mass and consider the point where the stick might fall, r x F is (x+l/2)/2*(x+l/2)/l*m*g
I would be 1/3*(x+l/2)/l*m*(x+l/2)^2+1/3*(l/2-x)/l*m*(l/2-x)^2
If I take the ratio r*F/I, I get that it is 3gm(1+2x)^2 over...
Homework Statement
There is a stick of length l moving at velocity v to the right on a table of height h.
Calculate the time and angle at which it loses contact with the table from the point where exactly half of the stick is off the table.
Homework Equations
F=ma
x=wt+1/2at^2...