Calculating the Time and Angle of a Falling Stick on a Table

[onlygirl]

Homework Statement

There is a stick of length l moving at velocity v to the right on a table of height h.
Calculate the time and angle at which it loses contact with the table from the point where exactly half of the stick is off the table.

Homework Equations

F=ma
x=wt+1/2at^2?

The Attempt at a Solution

So I think you need to model theta, the angle with the parallel it makes, as well as the position of the center of mass but I don't know how you would begin to do that as the point where gravity acts is constantly changing, meaning the angular acceleration is constantly changing..

 

[dharavsolanki]

This one's a good question.

Think of a simpler problem. Find out the length which should be off the table after which the stick might fall.

If the stick is in motion, will this length change? How does h figure into the answer?

 

[onlygirl]

So if I let x be the distance from the edge of the table to the center of mass and consider the point where the stick might fall, r x F is (x+l/2)/2*(x+l/2)/l*m*g
I would be 1/3*(x+l/2)/l*m*(x+l/2)^2+1/3*(l/2-x)/l*m*(l/2-x)^2

If I take the ratio r*F/I, I get that it is 3gm(1+2x)^2 over 2l^3m+24lmx^2, or (3g)/(2l) at both x=0 and x=l/2, points where there isn't any angular acceleration as the stick isn't falling, or is falling straight down. Before I proceed any further, what am I doing wrong?