Recent content by orange juice

In QM, we only measure a state using the definition of amplitude, not simply analyze it like what we do in classical physics.

Yeah, I studied that and I think a n-state system in QM can be analogous to a n-rank space, right? But my question is not this, Let me put my it this way: since ∣Φ>=∣1>*C1+∣2>*C2, which means that the state ∣Φ> has the amplitude C1 to be in the base state ∣1> and the amplitude C2 to be in...

Hi, we know that in a system with two base states, any state ∣Φ> of the system can always be described as a linear combination of the two base state:∣Φ>=∣1>*C1+∣2>*C2, where C1 is the ampitudes to be in on base state and C2 the other. My question is, does that mean the state ∣Φ> can only swing...

1) light does have energy; 2) you can get the E by both E=m*(sqr c) and E=h(bar)*w, BUT you should notice that m=m0/{1-[(v*v)/(c*c)]}, where m0 is the static mass and for photon, m0=0 (it's what you meant by "massless"); but for photon, v=c, so you get m=0/0, and you can't get E by the first...

I think The Feynman Lecture on Physics (Vol.3), section 3-2 "the two-slit interference pattern" can answer some of your puzzles, and as Feynman said there, "although we don't have the correct mathematical formula for all the factors that go into this calculation, you will see the spirit of it in...

You may go http://www.ets.org to find more details about GRE general. I just took it in June, and feel very relaxed now, lol. Good luck !