Recent content by Orims

Thank you! I finally got it! I used the fact that [OH-] ~= sqroot(Kb X [A-]), so I got [OH] from pOH and used the fact that since HA and NaOH were in equal volumes and concentrations, the [A-] would be half the concentration of HA. I got Ka from Kb (Ka= Kw/Kb) In the end I got a Ka of about...

1. This problem has been slowly eating me for the past 2 hours. I've done everything I can but I can't seem to answer it. The pH at the equivalence point in the titration of 100 mL of a 0.1M monoprotic acid solution with a 0.1M strong base solution is 8.12 at 25 degrees C. What is the Ka of the...