I need extra help. I'm studying for my Final Exam which is tomorrow and I cannot remember how to find forces of objects on an inclined plane. The question I'm having troubles with is:
A 12.5 kg crate is placed on a ramp that is at an angle of 22 degrees from the horizontal. Find the...
Final Exam Question Help!!!
HELP!!
I need extra help. I'm studying for my Final Exam which is tomorrow and I cannot remember how to find forces of objects on an inclined plane. The question I'm having troubles with is:
A 12.5 kg crate is placed on a ramp that is at an angle of 22 degrees...
There is a question involving a simple land rover that can be controlled to go a certain distance. It is two pop bottles connected spout to spout and attached around the middle is a metal tape measure which one would roll up and then let go for the rover to move. I have to explain the mechanics...
K...I found acceleration wrong. I realized that.
Acceleration = 1.733 m/s -squared-
So then do I go F=ma
F= 10.8 (1.733)
= 18.7164
So is that Fnet? If it is...then what?
Ok...so I have that. But what is SOOOOO EXTREMELY FRUSTRATING...IS WHAT DO I DO AFTER I HAVE ALL THAT!! The acceleration becomes 0.4163 m/s-squared-. F= ma.... that makes is 10.8(0.4163)=4.49604 N that's no where near the answer.
Ok....the puzzler. I haven't gotten really far. But this is what I have....
Vertical:
Delta X= -12.96 m
Vo= 0m/s
a= -9.80 m/s-squared-
v-squared- = vo-squared- + 2aDelta x
v= 15.94 m/s
v = vo + at
t= 1.626 s
Horizontal:
Delta x= 7.5 m
t= 1.626 s
v= ?
Delta x = vxt
vx=...
Delta X = 5.0 m
Vx= 4.613 m/s
t =?
Delta X = Vx(t)
t= delta x/ vx
= 5/4.613
= 1.083 s
So do I add 1.083 to the previously establish 1.626 and then get 2.709 for total time?
HELP!!!!! I am in grade 12 physics and my teacher gave us a puzzler for the weekend. I need serious help with it and all of my classmates cant figure it out either! The question is :
A 10.8 kg box is 5.0 m from the edge of a 12.96 m high cliff. Bob pushes the box over the edge of the cliff by...
Ok...
so I got vx to be 4.613 m/s. Then I use Pythagoras to find the velocity (vy-squared- + vx-squared- = v-squared) and I got it to be 16.59. Then to find acceleration I went:
a= V/t
= 10.20 m/s-squared-
Am I going right...because then I get F= ma
F= 10.8 (10.20)
=110.19 N
I don't...