Recent content by Palmira

Well I do not feel very smart. ∫csc2xdx/ 4= -cot x/4 +c go back to the triangle and it is -(√4-x2/ 4x) +c Thank-you so much!

Homework Statement ∫ dx/ x2 (√4-x2) Homework Equations x=2sinθ dx=2cosθdx sin2 θ= (1 + cos (2θ))/2 The Attempt at a Solution First attempt: Plug in the trig sub and get: ∫2cosθdθ/4sin2θ2cosθ The two cos θ cancel leaving ∫ dθ/ (4sin2θ) Now I replace the sin2θ with...