If I assume Vc = 0, then Vd = 5. And so Vb cannot be equal to zero.
Vab = 7v.
Va = 7 + Vb
I = I2 - I3
I = (Vad/10) - (Vcb/10)
I = Va/10 -5/10 +Vb/10
I = (7 + Vb)/10 -1/2 +Vb/10
I = Vb/5 + 7/10 -1/2
I = Vb/5 + 1/5
where Vb = -V
So
I = -V/5 + 1/5
Thanks! it also works the other way :)...
Using general form of Thevenin Circuit (according to Circuit Diagram):
I = (-V/Rth) + (Vth/Rth)
When I derive my I-V characteristics I compare the two equations.
Since what I calculated is:
I = -V/10 + 0.2
So
Rth = 10
Vth/Rth = I (when V= 0, intersection) = In = 0.2
This is...
I don't know which node to take as zero voltage. Either C or B or both.
Finding Out I-V characteristic of +V-. Considering Vb = 0.
ASSUMING V IS SOME LOAD
I = I2 - I3
I = ((Va - Vd)/10) - ((Vc - Vb)/10)
I = ((7 - 5)/10) - ((Vc - 0)/10)
I = 0.2 - Vc/10
Where Vc - Vb = V
Considered Vb = 0
So Vc...