Recent content by panoramarts

If I assume Vc = 0, then Vd = 5. And so Vb cannot be equal to zero. Vab = 7v. Va = 7 + Vb I = I2 - I3 I = (Vad/10) - (Vcb/10) I = Va/10 -5/10 +Vb/10 I = (7 + Vb)/10 -1/2 +Vb/10 I = Vb/5 + 7/10 -1/2 I = Vb/5 + 1/5 where Vb = -V So I = -V/5 + 1/5 Thanks! it also works the other way :)...

Using general form of Thevenin Circuit (according to Circuit Diagram): I = (-V/Rth) + (Vth/Rth) When I derive my I-V characteristics I compare the two equations. Since what I calculated is: I = -V/10 + 0.2 So Rth = 10 Vth/Rth = I (when V= 0, intersection) = In = 0.2 This is...

Lets assume V is some load in the picture above.

I don't know which node to take as zero voltage. Either C or B or both. Finding Out I-V characteristic of +V-. Considering Vb = 0. ASSUMING V IS SOME LOAD I = I2 - I3 I = ((Va - Vd)/10) - ((Vc - Vb)/10) I = ((7 - 5)/10) - ((Vc - 0)/10) I = 0.2 - Vc/10 Where Vc - Vb = V Considered Vb = 0 So Vc...