Recent content by patelnjigar

where is erroneous? The question is: List the cyclic Subgroups of U(30) My answer {<1>,<7>,<13>,<17>,<19>,<23>,<29>} however the answer key tells me {<1>,<7>,<13>,<19>,<29>} (leaving out <17>,<23>) Where am I erroneous?

Please help me. The question is: List the cyclic Subgroups of U(30) My answer {<1>,<7>,<13>,<17>,<19>,<23>,<29>} however the answer key tells me {<1>,<7>,<13>,<19>,<29>} (leaving out <17>,<23>) Where am I erroneous?

ba^(-1) = a^(-1)b aba^(-1) = aa^(-1)b aba^(-1)a = aa^(-1)ba ab = ba i seem that it done answers.

ab=ba a^(-1).ab.a^(-1) = a^(-1).ba.a^(-1) (a^(-1).a) b^(-1) = a^(-1).b(a.a^(-1)) e.b^(-1) = a^(-1).b.e b^(-1) = a^(-1).b is that right?? I hope that I made it...

i m sorry.. I lost and I don't understand what you talk about. Please help for that.

you mean that I have to make left and right.. make left: ba^(-1) = a^(-1)b => aba^(-1) = aa^(-1)b make right: ba^(-1) = a^(-1)b => ba^(-1)a = a^(-1)ba then what??

Show that whenever ab = ba, you have ba^(-1) = a^(-1)b. then you said that just answers: For example, a left multiplication by LaTeX graphic is being generated. Reload this page in a moment.: LaTeX graphic is being generated. Reload this page in a moment. => LaTeX graphic is being...

sorry.. I don't understand.. Please give me clear as that.. thanks.. smile..

Show that whenever ab = ba, you have ba^(-1) = a^(-1)b. I don't know how to slove problem. pls help me..

Same idea: let d = ba^(-1). ?? I seem that not enough ac=b a (a^(-1)b)=b, if ac=ad=b, then c=d (left cancellation).. I m sure that's right. da=b d=ba(a^(-1)), if ad=ac=b, then d=c (right cancellation) is that right?

if i want to say about ac=b proof: a (a^(-1)b)=b uniqueness if ac=ad=b then c=d (left Cancellation) How do I slove for da=b?? I need for that..

i m tried work on this.. GIVE a, b ∈ G SHOW c, d ∈ G ? ac=b da=b ac=b ---> proof: a (a^(-1)b)=b (IS THAT RIGHT? I THINK SO AND THAT'S RIGHT) da=b ---> proof: ?

I have tried set up matrices for that but not work. I don't know how to slove for this problem... Let G be any group, and let a, b ∈ G. Show that there are c, d ∈ G such that ac = b and da = b. Hint: you have to give an explicit definition for c and d in terms of a and b.

Please I need your help for that qustion and how do slove that qustion's problem. can you help me for slove for that? Pleasee Let G be any group, and let a, b ∈ G. Show that there are c, d ∈ G such that ac = b and da = b. Hint: you have to give an explicit definition for c and d in terms of a...