Recent content by Patrick Herp

Well, I'll try. Assuming the rest reference frame of the floor, if I set the "downhill" acceleration of the block relative to the prism as ##a_b## while the acceleration of the prism as ##a##, then Newton's 2nd law on the block perpendicular to the inclined plane is $$ N - mg \cos{\alpha} = ma...

The figure shows a block of mass m above a prism of mass M with a slope α. The block is connected to the wall through a massless rope and pulley system. Assume all surfaces are smooth. Determine the acceleration of prism M with respect to the ground. (Figure is the last attached image) I can...

For more clarification, I don't really "know" where this question comes from, I just found it randomly on the internet, among other questions that I think belong to high school questions, so I find it really weird that this particular part of the question suddenly jumps in difficulty. I did get...

The solutions for (a) and (b) are pretty straightforward, which I got 13 kW and 225 kW each, but when I try to solve for (c), I get stuck with this: $$ \begin{align} a &= \frac{F}{m} \nonumber\\ &= \frac{F_\text{max}-f(v)}{m} \nonumber\\ &= \frac{7(30)+6(30)^2 -70v-6v^2}{1.000} \nonumber\\...

Figure 1, Figure 2 *I'm using his textbook's rule in applying KVL here: $$ \begin{aligned} 21I_1 + 4.8I_3 &= 100 &&\textrm{Loop I (clockwise)}\\ 24I_2 + 4.8I_3 &= 0 &&\textrm{Loop II (clockwise)} \\ I_1 &= I_2 + I_3 \end{aligned} $$ From the above equations, I get ##I_3 \approx 4.63\textrm{...