Recent content by pchalla90

Homework Statement A simple open U-tube contains mercury. When 11.8 cm of water is poured into the right arm of the tube, how high above its initial level does the mercury rise in the left arm? Hint: At the level of the interface between the water and the mercury, the pressure on the left...

ahhhh! there we go. so errors with integration... thank you for correcting me! it works now. now off to figure out part b. thanks again!

and another thing: assuming that i have a conceptual error and not a mathematical error, i will also need assistance solving part b of the question: What will be the acceleration of the truck in 30 seconds if the water can enter the truck through a hole and remain inside? thanks again.

Homework Statement A hose can produce a horizontal stream of water at the rate of 600kg every 10 seconds as the water flows with constant speed of 30 m/s. Assume the water strikes the flat vertical back of a 2000kg truck. The water splashes out along the back of the truck without rebounding...

The problem with the butane torch is that this is not a metal pipe. It's a PVC pipe underground, but high enough that the ground doesn't shelter it from the cold. Basically, it's easily dug up, but I don't know how that could help.

Hi, I live in the northeast, well known for its heavy snowfall in the winter. Where I live, for the past few days, it has been raining heavily during the daytime and stopped at night. This has collected in various ducts and pipes meant to remove the water from the roof. At night, when the...

Thats what i assumed, but i guess mathman thought that the OP was in more dimensions...

I apologize, what i said earlier applied to one dimension only. For 2 or 3 dimensions, you have to break down the acceleration and velocity vectors into x and y or x, y, and z components, respectively. Then you have to have a defined +x and -x. same goes for y and, if youre in three...

oh! i used the word theory improperly. i meant to say hypothetical. my apologies. thanks for fixing that ZikZak.

Can you explain this in more detail, please? I am assuming that faster than light travel will be possible at some point in the future. I think that is my only assumption. Everything else to me seems logical. I should have been clearer on this earlier though. I was wondering whether...

If the object has positive velocity, but negative acceleration, it is slowing down. If the object has negative velocity, but positive acceleration, it is slowing down. If the object has positive velocity, and positive acceleration, it is speeding up. If the object has negative velocity, and...

I know that with todays knowledge, nothing can travel faster than light and nothing with mass can travel at the speed of light. I say with todays knowledge because physics is a living science which changes as new discoveries are made. Some of Einsteins findings overturned Newtonian physics...

Okay, so... ∫(-L/2,L/2) pR^2dr= (1/3)R^3p|(-L/2,L/2) =(1/3)(L/2)^3p-(1/3)(-L/2)^3p =(1/3)(L/2)^3p+(1/3)(L/2)^3p =(2/3)(L^3/8)p =L^3/12p p=M/L =(L^3/12)(M/L) =ML^2/12 Thank you so much for your help.

well, dm=pdL is what I am assuming... so ∫dm=∫pdL M=pL but shouldn't the right side of the above equation be a definite integral while the left is an indefinite integral? i think the right side of the above equation should go from -L/2 to L/2, but that raises the question of the limits...

Homework Statement Show that the rotational inertia of the rod about an axis through its center and perpendicular to its length is ML^2/12, where M is Mass and L is length from axis of rotation. Homework Equations ∫r^2dm=Mr^2 The Attempt at a Solution Well, you see the integral...