Recent content by perfect_piccolo

1. (a) Calculate the current through each ideal battery in the figure. Assume that R1 = 1.0 Ω, R2 = 2.0 Ω, ε1 = 4.0 V, and ε2 = ε3 = 8.0 V. Take positive current as that flowing through the battery from - to +. (See diagram) I just need some guidance about how to set this problem up...

[b]1. To push a 16 kg crate up a frictionless incline, angled at 15° to the horizontal, a worker exerts a force of 52.8 N, parallel to the incline. As the crate slides 1.50 m, how much work is done on the crate by the worker's applied force? b] So I got the first part of this question without...

All right new question :D The leg and cast in the figure below weigh 232 N (w1). (Assume w3 = 100 N and q = 39.2o). (See pic) So I know that Ft3 = Fg3 = 100N \SigmaFy2 = m2ay2 Ftyx + Fty3 - Fg1 = 0 Ft2 sin \alpha + Ft3sin\vartheta - Fg1 = 0 Ft2 sin \alpha +100sin39.2 - 232 N = 0...

ok thanks got it!

Homework Statement After falling from rest at a height of 29.8 m, a 0.596 kg ball rebounds upward, reaching a height of 23.9 m. If the contact between ball and ground lasted 1.68 ms, what average force was exerted on the ball? Homework Equations The Attempt at a Solution so I...

You are definiately my hero, you know that ;) I've only got one more question for tonite I promise *Grins* Two blocks of mass m = 12.6 kg each are fastened to the ceiling of an elevator, as seen in the figure below. (well obviously you can't see them) Anyways, the blocks are hanging...

ok so delta x = 1/2 (v initial + v final)t .792 m = 1/2 (328) t .792 m = 164 t 0.0048 = t (Is that right?) Then to find the acceleration v=v initial + at 328 = a(.0048) 68333 = a ??

Does that mean that my inital velocity is 0?

All right I've got another question for you :D A 5.26g bullet leaves the muzzle of a rifle with a speed of 328 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.792 m long barrel of the rifle? Ok, so I know my initial velocity is 328 m/s. I'm...

Hey thanks!

All right I'm really not understanding these forces... So the mass is = 1.2E + 7 kg and the pull from the Locomotive is 6.26E+5 N so I thought I would want to solve for acceleration and then figure out how long it takes to get to the velocity of 82.4 km/h So I said that F = ma so...

Homework Statement A freight train has a mass of 1.20E+7 kg. If the locomotive can exert a constant pull of 6.26E+5 N, how long does it take to increase the speed of the train from rest to 82.4 km/hr? What does the 1.20E + 7 kg mean? What is E? Thanks!

I don't know how to answer that question :( Does it use a projectile motion equation?

that's good :D But I'm still confused about how to answer the question. How high is the ball above the floor when its velocity vector makes a 46.4o angle with the horizontal?

so if tan(-46.4)=(Vy / Vx) ; -1.05 (2.86 m/s) = Vy -3.00 m/s = Vy ?