Recent content by personguy

So where would that come into this problem?

My friend tried it this way, but it didn't give the right answers: Torque = F.d = I.a I = moment of inertia a = angular acceleration F = force d = distance. The first torque made the wheel rotate from the rest until the speed gained an angular velocity of 530 rev / min The torque is 52Nm...

Angular Velocity: d theta / dt Torque: Tangential force times radial distance (Ft times r) = Fr sin theta = Fl

I did, I don't see anything.

No, I don't.

1. A wheel free to rotate about its axis that is not frictionless is initially at rest. A constant external torque of +52 N m is applied to the wheel for 22 s, giving the wheel an angular velocity of +530 rev/min. The external torque is then removed, and the wheel comes to rest 120 s later...