Recent content by Peter Halsall

The mass and the acceleration, but I don't really see what that's got to do with tension?

Homework Statement A locomotive has a mass of 40 tonnes. In one situation, the locomotive is pulling two trucks, each of mass 10 tonnes Calculate the tension in the coupling pulling the two trucks behind the locomotive. The coupling is positioned such that it is linking the locomotive and the...

I'm sorry, I don't understand what your asking, do you want me to prove it using Newton's 2nd law?

Homework Statement Two blocks, A and B , are being pushed on a frictionless surface by a froce of 30 N to the right, .Block A has a mass of 2.0kg, Block B, being pushed by Block A is 4.0kg. Calculate the magnitude of the force that block B exerts on Block A. Homework Equations f=ma The...

Ok so I have two equations Vertical component: 0=1/√2*u*t-5*t^2 Horizontal component: 3=1/√2u*t From this I can rearrange the horizontal equation to get t by itself and then substitute it into the vertical equation to attain u?

Could you use it for both?

x=u*t+(a/2)*t^2

Time? Time can't be different for either directions of motion, the direction has no effect on it whatsoever.

How do I know the displacement vertically? and I don't know what else is the same in terms of both motions. They both have the same initial velocity but the difference in acceleration (which for horizontal it must be 0, thank you) implies that the motions must be different.

How do we know the acceleration for the horizontal component? And what do you mean by 'initial velocities are the same in each direction, so that's one more equation' ?

Homework Statement An athlete can cover 3.0 m for a standing long jump. Assuming that this athlete jumps at an angle of 45 degrees to the horizontal. calculate the speed at which the jumper can launch herself from a standing start. Assume g =10 ms^-2 and no air resistance Assume that horizontal...