Recent content by Pezz

Consider two frames: S and S', with S' moving to the right along the positive x-axis or S at a relative velocity v. The origins of S and S' coincide at t = 0. A spherical electromagnetic wave leaves the origin of S the moment S and S' coincide, or at t = 0. If we consider the transformation...

I mean why can I not measure the object instantaneously in my own frame and enter it as dx.

The Lorentz transformation for motion in the same direction along the x-axis of two frames can be used to derive the length contraction formula. Say we are converting from dx to dx'. The t would obviously have to be 0. That would leave us with dx'=gamma(dx). My question is why dx here has to be...

I finally understood it... I was missing a small detail involving an equation that was right in front of me the whole time... thanks for offering your help, that was frustrating... I guess I should just take more time on understanding things :P

Hey all, Simple question yet it creating a lot of confusion in me and I need some clarification. This is an example given in a book I'm reading and I just don't understand one piece of it. In the S frame a completely inelastic collision between two particles traveling at each other at speed u...

Thanks for the link. I will definitely start reading it tomorrow as it's getting late here and I'm about to go to sleep. Before I go off, I thought of one thing that doesn't make sense to me and I know that there is an error in my thought process but I just can't seem to find it... Say a...

Thanks for the responses, it clears some stuff up. I think I'm overthinking the whole thing but it's only been a week since I've been introduced to all of these concepts of length contraction, time dilation etc. I hope it becomes clearer with time, I guess I'm just not used to thinking...

Hello everyone :). I'm new here and wasn't sure where to post my physics question so here I am in the homework help section as my question is homework related... The problem I'm having is of very basic nature however I might have some trouble wording it. I understand an event is something that...