Oh wow, I totally ignored the Y component. I realized the X would cancel out.
Assuming that my other calculation of E = 9x10^9 ((1.414 x 10^-6)/(.707^2)) is correct, then E1 and E2 would be cos45(25,459 + 25,459) or 36004 V/m
Does that look correct?
Thanks!
Isosceles rectangle triangle is copied from the question! lol
I tried to print screen and hopefully this will work: http://www.freeimagehosting.net/image.php?3c6c6c04ab.jpg
Thanks for any help
Homework Statement
1. Two point-charges of charges +q and +q are held at the corners of an isosceles rectangle
triangle, as shown in figure below. The absolute value of q is 1.414 μC. The distance d as shown in the figure is 0.5 m. The angle at A is 90. The gravitational forces are...
Well the answer for c should be 75 volts.
So maybe take the voltage from the battery given and subtract the absolute voltage difference (answer of part d) to get 75 volts?
Weird.
I drew it exactly as the problem displays. Maybe there is an issue with the question?
I would assume that the battery is supposed to be the other way, but I cannot be certain.
Homework Statement
Three resistors and two batteries are connected as shown in the figure. The magnitude and direction of the currents in the unknown resistor "R" at the right and the 6.0 ohm resistor on the left are shown in the figure. The current in the 4.0 ohm resistance flows from B to...
We've never talked about centripetal force in class so I doubt that the answer is related to that.
I do not believe we have to take into consideration relativistic effects.
Would a formula like F= BIL be more effective? The current seems to be the missing link in all the magnetic field...
Proton Beam therapy is an advanced technique to destroy tumors by concentrating a high energy beam of protons to a specific depth inside the body of a patient. These proton beams are produced by accelerators and steered to the patient-treatment rooms by magnets. In a particular cancer treatment...
I'm not sure what my final equation would look like. The original looks like
B= uI/2(pi)r
The pi would cancel out from the constant in the "u." I used this and still had the wrong answer. Any other ideas?
I'm having a difficult time applying the law as it is on the wiki page.
It says that the r should be squared. And times by four pi. That four pi would cancel out with the four pi from µ.
So I would just end up with r squared on the denominator?