- #1
PhilCam
- 46
- 0
Homework Statement
1. Two point-charges of charges +q and +q are held at the corners of an isosceles rectangle
triangle, as shown in figure below. The absolute value of q is 1.414 μC. The distance d as shown in the figure is 0.5 m. The angle at A is 90. The gravitational forces are negligible.
a) Find the direction and the magnitude of the total electric field at
the apex A. (Use the coordinate system shown in figure by x and y.)
I don't have the drawing up but if you can imagine a triangle with the top angle equaling 90 degrees and the two bottom angles having charges of +q. A line descending from point A along the y-axis dissects the bottom portion of the triangle, divides it in, each side being distance d.
I know, using Summation that Etotal = E1 + E2 and that E1 and E2 are the same because they have the same charge.
I know the equation for the magnitude of an electric field is E=k(q/r^2)
To find r I used the equation .5/sin 45 = x/sin 90, ending with an r value of .707m
So I know that E = 9x10^9 ((1.414 x 10^-6)/(.707^2))
Using that equation I end with a value of 25,459V/m for E1. Using my previous equation, I find that Etotal = 25,459 + 25,459 = 50,918 v/m.
That is incorrect, can someone tell me where I slipped up? Thanks.