Here's the question:
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95.0 mL of 2.1 M H_2SO_4 _(aq) was needed to neutralize 52.0 mL of NaOH _(aq) . What was the Molarity concentration of the sodium hydroxide solution?
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Here's what I did:
Reaction: H_2SO_4 + 2 NaOH -> Na_2SO_4 + 2H_2O...
I got that the answer should be either: 16.4 mL or using 0.5 mol
then the volume should be (0.05 mol) / (0.61 M) = .082 L = 8.2 mL
Here is the question which answer would it be: 16.4 mL or 8.2 mL?
I guess the larger question is don't I have to take into account that according to the...
There would be .025 mol of OH in NaOH and .036 mol of OH in KOH.
Here's what I think the solution should be now. See if this is right.
From before. I have 0.05 mol of H_2SO_4. Based on the reaction:
H_2SO_4 + 2XOH -> X_2SO_4 + 2H_2O where X is either Na or K ( I don't think it matters...
They're both strong bases that disassociate in water to form OH^- and either K^+ or Na^+.
But, you would still have different moles of each so I'm still stuck.
Here's the question:
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A base stock solution is prepared by dissolving both 1 gram of sodium hydroxide and 2 grams of potassium hydroxide in enough water to prepare 100 mL of solution.
How many millimeters of this base stock solution are required to neutralize 100 mL of 0.50 M...
Here's the question:
What is the boiling point of a solution that contains 1.25 mol CaCl_2 in 1400g of water?
Now, I know that I have to take into account the fact that CaCl_2 disassociates in water to form ions.
I thought the effective molality here would be 3 * 1.75 m since there are...
Hi.
I'm having a hard time solving this problem.
I have to find the identity of element X in the following reaction:
XCl_2~+~Cl_2~-->~XCl_4
knowing that 10 grams of XCl_2 + 2.55 grams of Cl_2 produces 12.55 grams of XCl_4.
Now, I thought about doing mass percent composition that...