thanks holezch, but luckily for me I was able to find a formula on my own in time and the teacher told me that it was right...although i did it this way and am getting the same answer...thanks!
Homework Statement
If the balloon in the diagram drawn below is accelerating upwards at 0.40 m/s2, calculate the tension in each piece of rope. Assume that the rope has no mass.
http://img261.imageshack.us/img261/964/capture2gm.png
http://img261.imageshack.us/img261/964/capture2gm.png...
ok i think i might have gotten it...is this all i have to do:
m=94.0kg
a=9.8m/s^2
CD=54kg/m
v=?
F_fric=?
Step 1
F_fric=ma
F_fric=94.0*9.8
F_fric=921.2m/s
Step 2:
921.2=54*v^2
921.2/54=v^2
17.1=v^2
√17.1=v
4.1=v
v=4.1m/s
So the above is wrong? LOL I know I do not udnerstand the question which is why I'm asking it! I would draw a FBD but not sure which way tension would be going...Fg would be down...and then Fapp would be up, where does Ft come in all this? I've also googled this and it seems that
ma=m(g+a)...
Ok guys this is how far I got from what I understood...can somone tell me if this is right and how to get to the next step please? Thanks in advance...this sites been a real life saver!
Rope 1
a=0.40m/s^2
m=15kg
g=9.8m/s^2
F_t=?
F_g=?
Step1
F_g=mg
F_g=15*9.8
F_g=147m/s^2
Step2
F_t=
actually I've been trying this for almost 45 minutes now and the thing is i don't know what tension is...is tension Fg? where Fg=m*a and it would me 15*.4?
Homework Statement
If the balloon in the diagram drawn below is accelerating upwards at 0.40 m/s2, calculate the tension in each piece of rope. Assume that the rope has no mass.
http://img261.imageshack.us/img261/964/capture2gm.png
http://img261.imageshack.us/img261/964/capture2gm.png...