Recent content by physicsforus

By golly, Jeeves I think I have it. I did the Math and got -25\sqrt{}2 which broke down to -35.3553/2 which came to -17.67767ohms (or that might be positive not quite sure) That is actually the second time I got some kind of nerd snipe thing because of this question...

I know 0 ohms is not right. so new calculations: 1 ________ 1 + 1 + 1 _ __ __ = 3 25x 25 25 X ___ = ____ = 8.3333X 25x 3 Now I have just confused myself...grrrr. so frustrating.

R_{eq} = \frac{1}{\frac{1}{25} + \frac{1}{25+x}} Req=1/.08x Req=12.5x x=2(12.5x) x=25x x + -25x= 25x + -25x x+-25x =0 -24x=0 x=0 so between A and B there is no resistance? (my algebra may be a little rusty especially at 5:20 in the morning)

Thanks for your help, but I am still completely confused. This was for a game I am playing with a bunch of people and we are allowed to use any resources. I was hoping to learn something new, but this is way over my head. Hopefully one of the other people will understand all of this.:frown...

I think I understand. (I have never done this sort of thing before, so please don't get too irritated) Req= R/n So given that R=25 ohms I take 25/3=8.33 ohms x=2(8.33)=16.67 ohms Am I close at all? or am I still not understanding?

Homework Statement What is the resistance of the (semi-)infinite resistor chain below, between points A and B, if R = 25 ohms? The Attempt at a Solution I am not sure where to begin exactly, but I am thinking of this formula: VAB=VB-VA=∑ε-∑i.R or...