By golly, Jeeves I think I have it.
I did the Math and got
-25\sqrt{}2
which broke down to
-35.3553/2
which came to
-17.67767ohms
(or that might be positive not quite sure)
That is actually the second time I got some kind of nerd snipe thing because of this question...
I know 0 ohms is not right.
so new calculations:
1
________
1 + 1 + 1
_ __ __ = 3 25x
25 25 X ___ = ____ = 8.3333X
25x 3
Now I have just confused myself...grrrr. so frustrating.
R_{eq} = \frac{1}{\frac{1}{25} + \frac{1}{25+x}}
Req=1/.08x
Req=12.5x
x=2(12.5x)
x=25x
x + -25x= 25x + -25x
x+-25x =0
-24x=0
x=0
so between A and B there is no resistance?
(my algebra may be a little rusty especially at 5:20 in the morning)
Thanks for your help, but I am still completely confused. This was for a game I am playing with a bunch of people and we are allowed to use any resources. I was hoping to learn something new, but this is way over my head. Hopefully one of the other people will understand all of this.:frown...
I think I understand. (I have never done this sort of thing before, so please don't get too irritated)
Req= R/n
So given that R=25 ohms
I take 25/3=8.33 ohms
x=2(8.33)=16.67 ohms
Am I close at all? or am I still not understanding?
Homework Statement
What is the resistance of the (semi-)infinite resistor chain below, between points A and B, if R = 25 ohms?
The Attempt at a Solution
I am not sure where to begin exactly, but I am thinking of this formula:
VAB=VB-VA=∑ε-∑i.R
or...