I completed the dot between k and r within F.
k = (kx, ky, kz)
TA said to use r=(x,y,z)
thus the function becomes
F(xkx+ yky+zkz)
∇2F(xkx+ yky+zkz)=0, right?but then how would k2F(xkx+ yky+zkz)=0?
Homework Statement
Prove that F(k•r -ωt) is a solution of the Helmholtz equation, provided that ω/k = 1/(µε)1/2, where k = (kx, ky, kz) is the wave-vector and r is the position vector. In F(k•r -ωt), “k•r –ωt” is the argument and F is any vector function.
Homework Equations
Helmholtz...