Recent content by physicsuwa

Dick. I am sorry man. I just saw it and it was literally a Eureka moment on the train. I don't know how I could have been so stupid. Thanks for sticking with me. Appreciate all the help.

Sorry. I don't understand what you mean by "in terms" of ω and A

I gave them in the original question. but perfectly happy to repeat. Max Speed = 3.5m/s and max acceleration is 15m/s^2

Ok. Well what i have done is in regards to the velocity and acceleration is differentiated the distance to get velocity and differentiated that to get acceleration. v = ω*A*sin(ωt+∅) and for acceleration is a=-ω2*A*cos(ωt+∅). I am quite sure that's right but let me know if its not. and for...

I did that actually. I got expressions for both but I am missing amplitude so can't gain much from that. I tried to used f=-kx and substitute that into the ω = √k/m but that didn't work out either as I am missing x. Anyway. I just need a direction or that clue that will just crack this open for...

Homework Statement A 50g mass is attached to a spring and undergoes simple harmonic motion. It's maximum acceleration is 15m/s and maximum speed is 3.5m/s. Determine a)angular frequency, b) spring constant, c) amplitude. Homework Equations ω = √k/m X(t) = A*cos(ωt + ∅) The Attempt at a...