Recent content by physicswork

Thanks for fixing the title :)

Hmm so if my u = 1.79 × 10–3 N ∙ s / m2, A = 0.80m x 1.20m, v = 0.50 m/s, and y = .10 mm I should get... F = uAv/y = 1.79x10-3 Ns/m2 * (0.80m x 1.20m) x 0.50 m/s / (0.10 mm x 10^-3 m/1mm) = 8.6 N Can someone please check my math/logic and that my variables are correct? Is "0.10 mm" the right...

Homework Statement The block of ice (temperature 0°C) shown in Figure P9.57 is drawn over a level surface lubricated by a layer of water 0.10 mm thick. Determine the magnitude of the force needed to pull the block with a constant speed of 0.50 m/s. At 0°C, the viscosity of water has the...