Recent content by Physkid12

Brilliant! I'll try your method of getting the equilibrium points now! I really appreciate your help, you're a maths hero!

So are my equations of motion correct now? :)

Hi there thanks for your response! I've updated my eq. of motion based on your feedback, please let me know what you think ##\ddot{X} = X(\dot{\theta}^2 -k/m) -g(1-cos\theta) ## I'm struggling to change this one though as I thought the 1/2 cancels with the squared term when you differentiate...

Homework Statement A long light inflexible rod is free to rotate in a vertical plane about a fixed point O. A particle of mass m is fixed to the rod at a point P a distance ℓ from O. A second particle of mass m is free to move along the rod, and is attracted to the point O by an elastic force...

Hi there, I am also struggling on this question? I get the same Lagrangian except the potential of the spring is 1/2*k*x^2. Can anyone explain why this L is wrong?

So would it be correct to use polar coordinates then?So then r would be the distance for the 2nd particle and it is related to the kinetic energy by x=rcosθ y=rsinθ and the first particle has fixed r=l? Thanks for your swift response!

Homework Statement A long light inflexible rod is free to rotate in a vertical plane about a fixed point O. A particle of mass m is fixed to the rod at a point P a distance l from O. A second particle of mass m is free to move along the rod, and is attracted to the point O by an elastic force...