Oops! You're right, I got confused with the first integral, but is the second integral correct, because I'm not getting ##\frac{R^2L}{z^2}##
\displaystyle{ \vec{E} = \frac{2\pi}{4 \pi \varepsilon_0} \rho_0 \hat{k} \int_{\frac{-L}{2}}^{\frac{L}{2}} dz' - \frac{2\pi}{4 \pi \varepsilon_0} \rho_0...
Homework Statement
Finding the electric field outside of a uniformly charged solid cylinder, of length L and radius R, at any point of its axis.
Homework Equations
\displaystyle{ \vec{E} = \frac{1}{4 \pi \varepsilon_0} \int \rho(r') \frac{(\vec{r} - \vec{r'})}{\left| \vec{r} - \vec{r'}...