Recent content by piygar
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Bending shear stress distribution
It comes 6.12 at the neutral axis with zero Poisson ratio. (Tried with higher order Hexa, Hexa20 elements and got same result, as i had shear locking effect in mind)- piygar
- Post #7
- Forum: Mechanical Engineering
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Bending shear stress distribution
Thanks for reply. Wanted to understand the corners/edges effect clearly. Also plotted the horizontal shear stress (due to vertical shear load!) on the same cross-section and got this. Horizontal shear is small but not numeric zero. Discussed with a colleague and suspicion pointed to Poisson's...- piygar
- Post #5
- Forum: Mechanical Engineering
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Bending shear stress distribution
Shear stress at neutral axis along the width varies from 5.15 at the center to 8.07 at the either end of the width. Have inserted fringe plot with spectrum. I applied 100 unit shear load at the cantilever tip so according to formula max shear stress at center should be 1.5* 100/(6*4) = 6.25- piygar
- Post #3
- Forum: Mechanical Engineering
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Bending shear stress distribution
I modeled a simple cantilever rectangular beam in Patran of (L,W,H = 100, 6, 4) with Hexa8 elements and applied a vertical shear load (upwards) of some magnitude at the free end. Ran in Nastran and plotted the vertical shear stress distribution on a cross-section in middle of length (in order...- piygar
- Thread
- Bending Distribution Shear Shear stress Stress
- Replies: 7
- Forum: Mechanical Engineering
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Deflection of tapered beam cantilever
This is certainly possible to derive eq'n of delection. You will need to derive the deflection equation for you case, from equation: E*I*d2y/dx2 = -M,where I is varying with position of section, and will be a function of x. Therfore E*d2y/dx2 = -M/Ix, and integrate this equation twice...- piygar
- Post #2
- Forum: Mechanical Engineering