Recent content by Platon7

  1. P

    Bullet colliding with wood block - too many unknowns

    but when we assume that the bullet has penetrated and left the block, can we solve the problem?
  2. P

    Bullet colliding with wood block - too many unknowns

    yeah, because after dividing both parts for (m1+m2) we will get sth, that I have already mentioned above
  3. P

    Bullet colliding with wood block - too many unknowns

    do you mean (m1+m2)*g*h = (m1+m2)*u^2/2?
  4. P

    Bullet colliding with wood block - too many unknowns

    I didn't really understand that, so you mean, m1*v1^2 = (m1+m2)*g*h. I'm not sure about the right part of equation
  5. P

    Bullet colliding with wood block - too many unknowns

    oh, now I see, then we can find h using (v^2-v0^2)/(2*a), right?
  6. P

    Bullet colliding with wood block - too many unknowns

    I don't know, rectilinear also, we know the velocity before penetrating
  7. P

    Bullet colliding with wood block - too many unknowns

    oh, yeah, v'1 = v'2 = u, then we can calculate u, but what's next step?
  8. P

    Bullet colliding with wood block - too many unknowns

    m1*v1 = m1*v'1 + m2*v'2, where m1 and m2 - are masses of bullet and block respectively, v1 - velocity of bullet before the collision, v'1 and v'2 - after
  9. P

    Bullet colliding with wood block - too many unknowns

    it is a full statement as I have written
  10. P

    Bullet colliding with wood block - too many unknowns

    Yeah, I didn't think about that and it makes sense, because while penetrating almost for sure some energy was spent on heating the block, but then how am I suppoused to move further with solution?
  11. P

    Bullet colliding with wood block - too many unknowns

    As far as I understood, goes through and continues moving.
  12. P

    Bullet colliding with wood block - too many unknowns

    I don't know, the system seems to be closed
  13. P

    Bullet colliding with wood block - too many unknowns

    I have tried the following. Firstly, we can write the law of conservation of impulse m1*v1 = m1*v'1 + m2*v'2, that is the first equation for the system. Then we can write the law of conservation of energy, like KE1 + KE2 = PE1 + KE'2, and then we can substitute formulas, but as far as I can see...