http://tutorial.math.lamar.edu/Classes/CalcI/Optimization.aspx
I think you can make an equation with the sine law for R but it will still have an unknown theta in it.
You know the unknown angle must be less than 140. R = 14*sin40/θ.
There is no limit at x if the function jumps at x. So if you find that the "limit" of f(x) at x approaching from the left is different from approaching from the right, you say there is no limit at x.
Draw a circle. Now draw an equilateral triangle with one point at the center and the other two on the circumference so it has side lengths of r. Extend one of the points on the the circumference perpendicular to the base until you have a right angle triangle that encompasses the equilateral...
Thanks I got it now. I had been down that route but for some reason I just never took it all the way..
Here is the solution I got, though it probably isn't the best.
[SIZE="4"]6sin2x-3sin22x+cos2x=0
using Pythagoras and double angle identities
5sin2x - 12sin2xcos2x + 1 = 0
sin2x(5 -...
I have probably put around two hours into this question to no avail!
6sin2(x) - 3sin2(2x) + cos2(x)=0
I have too many fruitless attempts to bother typing them all out.. But my instincts at first told me that this looks like a quadratic equation.
I have tried using the double angle...