Looks like I stated the problem from a different angle by talking in terms of Bayesian probabilities.
In reality what we have is measurements of performences, then the normal distribution law comes into play, when we try to predict the winner. In this way only my approximate solution with the...
I deleted a post because I wrote something in error.
I have done Bayesian probability at college and some other things like the Poisson process.
In this problem, in real life, we measure throw distances and therefore the normal distribution comes into play if you look at it from a rigorous...
It's (2 out of 4) x (1 out of 15) / (3 out of 19) = 6 x 15 / ( 17 x 18 x 19 / 6 ) = 0.093
see this also
https://www.physicsforums.com/showthread.php?t=226637
It has something to do with the host's atitude towards the contestants of the tv show I believe and there are two solutions as a result ("friendly host" and "tricky host").
Well I 'm a little baffled.
I suppose -in real life- those percentages 60%, 60%, 70% might derive from statistical observations and logbooks.
So if A throws 85 meters plus-minus 2 metres and if B throws 84.5 meters plus-minus 2 metres -as measured by the sports statisticians- that gives us the...
My problem is this.
We have three javelin throwers A,B and C.
It is known that A defeats B with probability 60%, B defeats C with probability again 60% and A has the better of C with 70%.
What are the a-priori probabilities of A, B, C winning the 3-way contest ?
If in general we have N...