Recent content by pogge123

mass = n x MM Therefore 0.25 moles X 18.015 molar mass =4.50 g then Volume = mass/density Volume= 4.50g/ 1.0g cm^3 Volume= 4.50 mL??

1 mol?? or is it 0.25 Our lab manual is very unorganized.. molar mass is 18.0153 g/mol.

if i recall density of water is 1g/ml. So to find Volume you use D=m/v But what is the mass in this case?

there's 4, which now makes me confused because the experiment was suppossed to create n-propyl Propanoate. Whiich i thought was CH3CH2C(O)OC3H7 or C6H12O2? Also wouldn't you just expect there to be One mole of n-propyl Propanoate and one Mole of H20? How do you find the expected volume of...

Homework Statement Calculate the volume of water expected if the yield of ester were 100%. 19.0mL of n-propanol (0.25 Mol) 18.5mL(0.25 Mol) propanoic acid. 5 drops concentrated sulfuric acid Homework Equations The Attempt at a Solution C3H7OH + C3H5COOH ---> C6H12O2 + H2O (...