CHEM: Calculate the volume of water expected if the yield of ester were 100%.

[pogge123]

Homework Statement

Calculate the volume of water expected if the yield of ester were 100%.
19.0mL of n-propanol (0.25 Mol)
18.5mL(0.25 Mol) propanoic acid.
5 drops concentrated sulfuric acid

Homework Equations

The Attempt at a Solution

C3H7OH + C3H5COOH ---> C6H12O2 + H2O ( not sure this is right)

 

[Borek]

Reaction is wrong - how many carbons in propanoic acid?

However, this is a very simple case of 1:1:1:1 reaction - how many moles of products do you expect?

 

[pogge123]

there's 4, which now makes me confused because the experiment was suppossed to create n-propyl Propanoate. Whiich i thought was CH3CH2C(O)OC3H7 or C6H12O2?

Also wouldn't you just expect there to be One mole of n-propyl Propanoate and one Mole of H20? How do you find the expected volume of water from that?

So balance equation = 10C3H7OH + 6C3H5COOH = 9C6H12O2 + 4H2O?


** Our lab manual says C3H5COOH is propanoic acid**

So I am assuming that's a typo and should be C3H6O2 Which then made my orignal equation correct

C3H7OH + C3H6O2---> C6H12O2 + H2O

 

[Borek]

Your manual is wrong, this is a classic mistake.

What is water density?

 

[pogge123]

if i recall density of water is 1g/ml.

So to find Volume you use D=m/v But what is the mass in this case?

Your manual is wrong, this is a classic mistake.

What is water density?

 

[Borek]

if i recall density of water is 1g/ml.

So to find Volume you use D=m/v But what is the mass in this case?

How many moles? Molar mass?

 

[pogge123]

1 mol?? or is it 0.25 Our lab manual is very unorganized.. molar mass is 18.0153 g/mol.

 

[Borek]

If they react 1->1, and you start with 0.25 mole, how many moles of water are produced? How many grams it is?

 

[pogge123]

mass = n x MM
Therefore 0.25 moles X 18.015 molar mass =4.50 g

then Volume = mass/density

Volume= 4.50g/ 1.0g cm^3
Volume= 4.50 mL??

 

[Borek]

Wasn't that hard