Recent content by ponomous

OHHHHH oops... That is my fault for using notation that is nearly identical to the function notation. Thanks, I have the right answer now. I know on some forums they have a thank button or something, is there something like that here? You have been most helpful.

So when i run through the two formulas i end up with 20(2000) + 20 Rth = Vth 60(10,000) + 60Rth = Vth Solve and get -14,000 = Rth This gives me a Vth of -240,000 When i substitute i get IL(20,000) = -240,000/ (20,000 - 14,000) Which gives 2 mA

Hey cepheid, I understand what you are saying, and it makes sense, but i have run through this now 8 times and I am always getting 2 mA instead of 4. I can't find anything in my work that is wrong, any ideas? Thanks

Homework Statement When a 2-kΩ load is connected to the terminals A–B of the network in the figure, the current through the load is IL = 10 mA. If a 10-kΩ load is connected to the terminals, IL = 6 mA. Find IL if a 20-kΩ load is connected to the terminals. 2. The attempt at a solution I...