Recent content by poopoo16

how do i calcuate voltyage drop arcross the 6ohm? do i use P=I^2R?

so... R=10 V=10 I=V/R hence I=10/10? meanning P=IV P=(1)10...?

well, after u combine the 2 parallel ones, its no longer going thru the 20 per se right, its going thru a 6 and a 4?...soo... it then a series right?

that s my question... don't know how to treat the 6 ohms... do i add it to the 4? and then use P=IV where I=V/R?...if i do that, its give me 1...and that is not the right answer...

ok consider the circuit. what is the power loss in the 20 ohm resistor in J/s? ok so what i did was that... and i don't know where to go after... please help