For x I have v_finalx = (2m)v_final * cos (phi). For y i have v_finaly = (2m)v_final * sin (phi). This would mean that tan (theta) = cos (phi)/sin(phi). I've already tried atan (cos(phi)/sin(phi).
Homework Statement
What is the angle theta with respect to north made by the velocity vector of the two cars after the collision?
Express your answer in terms of phi. Your answer should contain an inverse trigonometric function.
the cars are both of mass m.
Homework Equations
I already found...
In case anyone else has a similar problem I'll explain how I found the answer. I found the area of the triangle with. A = .5 * (36, force max) * change in t. A is equal to weight in kg * v_1 - (weight in kg * v_2). Therefore 4.2 = .5 (36) * change in t.
I'm still stuck on this one. I know that i can calculate avg force by impulse / change in time, but I'm not sure how to find avg force in this situation.
Homework Statement
A 700 g air-track glider collides with a spring at one end of the track. The figure shows the glider's velocity and the force exerted on the glider by the spring.
How long is the glider in contact with the spring?
Homework Equations
F(t_1-t_2)=mv_2-mv_1
The Attempt at...