Recent content by Priyanka88

Damn i got the equation! Thanks man Check this if anyone wants to see the differential equation

@haruspex please explain how that differential equation came... Cause i tried and mine is different... The rest of all i understood!

Or just consider a value d as its linear mass density! That'll be easier

Well i said there is friction... Which means it is massed! If anyone is really solving it take it M1 if you want!

Yes! And my question is concerned with your 2nd case! Obviously the string is massed here! I am unable to make that tricky equation! That's where i need help

Yes exactly!

My question has nothing to do with a capstan... Take a rope and a cylinder... If you wind the rope around it and attach a mass to it, yoyou' see that it will slide but if the no. of windings is enough it won't slide due to the friction holding the rope acting between the cylinder and the rope...

Oh ohk i got this... Ah let me go through it once though. Thanks.

Yeah i know it isnti about rotation, actually we were given this question just after rotation, anyway sorry about that... And the coefficient of friction is to be taken n. And the other end will require no force at the other end if there is friction because friction will be opposing the weight...

I get it! I do know it's complications. I need a value with respect to coefficient of friction and mass m. I got why it's so hard... That's why I asked this doubt

Yeah i know. The twig is supposed to be considered as a cylinder. So the surface is of a plain cylinder! Even the string is a plain and cylindrical

Check now!

A mass m is tied to a string which is wrapped to a twig of a tree. How many minimum times should we wrap the string so that it doesn't fall? Here is what i got... 1.There is friction between the twig (or fixed cylinder) and the string. 2. if the total friction between the string wrapped around...