Recent content by pro.in.vbdnf

..while keeping the left radical? I wonder if there is an identity of the form \sqrt{cos(x)} = ... cos(x) ...?

\sqrt{cos(x)} = \sqrt{2 cos^{2}\left(\frac{x}{2}\right) - 1} So there is no way to get rid of the right hand radical?

(Yes, I meant \sin^2(x) + \cos^2(x) = 1.) What are their names? By the way, is there a difference between the [tex] and [itex] tags? And is there a way to vertically center the LaTeX images with the text?

Does that mean \sqrt{cos(x)} has an identity in terms of cos(x)?

Thanks for your help! The identities I was missing putting together were sin^{2}(x) + cos^{2}(x) = 1 and cos(2x) = cos^{2}(x) - sin^{2}(x). So cos^{2}(x) = \frac{cos(2x) + 1}{2}. I'll have to remember that.

I noticed that the graphs of sin(x) and sin(x) ^ 2 are very similar. So I offset sin(x) ^ 2 to exactly match sin(x): sin(x) = 2 sin^{2}\left(\frac{x}{2} +\frac{\pi}{4}\right) - 1 Is this right, or is it an illusion? I haven't been able to find any identity that this is based on. If it is...